[Bondjrno]

Originally Posted by qbeac Originally Posted by Dsmoke Oh, I just saw this post. If you're still doing the experiment, I'd love to join in.

But, the main question is this one: do you think you will be capable of reading the two words written on the paper and report on them correctly? Have you ever tried to do something like that: reading letters or numbers? Reading is an immediate trigger for me to wake or snap out of trance. I don't know why. It's possible that two words may not present much of a problem for me, but I can't guarantee that. If this is what you're doing and you're not interested in someone who may have difficulties, I'm probably not the best person to participate in your study. However, if you ever decide to work with other methods, I would be happy to work with you. Hi Dsmoke, we would be glad to work with any projector who can get even a very small percentage of correct readings on the two words from the dictionary. A priori, we don’t have in mind a fixed minimum level, but to give you a general idea of what would be considered acceptable values, we believe that guessing the correct words “around” 1 every 20 times (5% of the times) would be a good starting point. If you get 1 out of 25, or even 1 out of 30 more or less, yes, that would also be ok to begin with.

Or course if you can get a higher percentage than that, it would be great. But such small percentages (3%, 5%...) would be ok as a starting point. And maybe if you practice a little bit, you’ll get better at it, we’ll have to see.

And I’ll explain you the reason why those small percentages (3%, 5%) are acceptable to begin with: because the “control group” (who do not have an OBE) will probably be even lower than that. We don’t expect for the control group to get hardly any correct reading at all, simply because the probability of guessing by chance the two words from the dictionary, is very, very, very low. It is much easier to guess a lottery number, than to guess the two words. Therefore, the control group will probably get zero correct readings almost every time. And what we pretend to do is to compare the results in both groups: the control group (without OBE) and the subject group (with OBE).

Let me give you an example taken from Table 1 of the Agnostic Method:

The complete Table 1 is in Post #3, pag. 1 at link:
http://www.astralpulse.com/forums/viewtopic.php?t=20907

These are only two of the variants from Table 1:

2.- "2 ordered words taken at random from a dictionary" (calculated on the base of 10,000 words of a total of 59,000; 17%).
Probability of guessing by chance one time: 1.e-8, = 0.00000001
(7 zeros after the decimal point).

5. - "Cipher of the 5 random numbers”. Spanish well known lottery number "Cupon de la ONCE." Example: 78153
Cupon URL: http://www.once.es/home.cfm?opcion=1&orden=1&ultimos=ok
Probability of guessing by chance one time: 1.e-5, = 0.00001
(4 zeros after the decimal point).

See? If you think about it, many people have bought the lottery number “Cupon de la ONCE” during many years, and have not guessed it a single time. And guessing correctly the two words from the dictionary is even much harder than that.

Thanks. qbeac.