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**Cemeuncex** · 04-05-2011, 12:51 PM

I have to reduce this long string of algebra and I want to compare my answer to yours, it is so long and tedious that it is error-prone. But for those of you that enjoy this, be my guest:

$\\Q_1=\frac{a-\frac{\lambda_1}{2}}{3b} \\\\Q_2=\frac{a-2\lambda_1}{3b} \\\\TR_1=aQ_1-bQ_1^2-bQ_1Q_2 \\\\TR_2=aQ_2-bQ_1Q_2-bQ_2^2$

Reduce TR1 and TR2... then, if you are really, really bored, continue:

$\\TC_1=\frac{a\lambda_1-.5\lambda^2_1}{3b} \\\\TC_2=\frac{1.5a\lambda_1-3\lambda^2_1}{3b} \\\\P_1=TR_1-TC_1 \\\\P_2=TR_2-TC_2$

What a pain in the ass! I will post my results once I am done!

04-05-2011, 12:51 PM	#1
Cemeuncex Join Date Oct 2005 Posts 407 Senior Member	Any bored math people on? I have to reduce this long string of algebra and I want to compare my answer to yours, it is so long and tedious that it is error-prone. But for those of you that enjoy this, be my guest: $\\Q_1=\frac{a-\frac{\lambda_1}{2}}{3b} \\\\Q_2=\frac{a-2\lambda_1}{3b} \\\\TR_1=aQ_1-bQ_1^2-bQ_1Q_2 \\\\TR_2=aQ_2-bQ_1Q_2-bQ_2^2$ Reduce TR1 and TR2... then, if you are really, really bored, continue: $\\TC_1=\frac{a\lambda_1-.5\lambda^2_1}{3b} \\\\TC_2=\frac{1.5a\lambda_1-3\lambda^2_1}{3b} \\\\P_1=TR_1-TC_1 \\\\P_2=TR_2-TC_2$ What a pain in the ass! I will post my results once I am done!
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