[Vikonbarius]

Let's see here, our givens are:
a = 2.8m/s^2
initial velocity = 0m/s
final velocity = 37m/s

Remember that change in velocity = a * t; and we need to know time before we can go further.

So, solve for t by doing delta v / a = t and get 13.214... seconds.

So now that we have our time, we can solve for our delta x(change in position). We do this by using the equation: delta x = (v initial)t + .5(at^2), but since initial velocity is 0, it simplifies to: delta x = .5(at^2), which equals 243.9m and then do your sig figs.

That AP Physics class I am taking is pretty insane...(just wait until you get to friction)

There are a few other ways to get this, but they all involve basically the same thing. Above was done using the v^2=2a(delta x) method