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Old 03-27-2007, 06:53 PM   #9
furillo

Join Date
Oct 2005
Posts
439
Senior Member
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Huh? That's like saying you need a formula where 1+1=3 and solving it by writing it as 1+1=3 - or am I missing something?

What you need, IMO, is something like (100*(75-45)/45)k=40%, in this case k=0.6 (I think). However it may not be the same in other cases, it may be progressive, proportional, exponentially increasing etc - hence the request for other samples.

[edit] I mean (100(b-a)/a)k=x%, where a is initial value, b is new value, k is the modifier (term?) and x is the resultant.
I don't think that is what he is looking for but without the context its impossible to know. When you are looking at percent difference you need to define a baseline to which you are referencing the change. Without knowing the problem, it could be either the 45 or the 75 but for whatever reason its the 75. Generally these problems are associated with a time event, i.e at time A the value is 75 and at time B the value is 45 therefore the percent difference when moving from time A to time B is 40 %.

In another context, the 75 could be the exact value while the 45 is some approximation. In such caluclations the exact value is what you divide by to find the percentage error (assuming you take the absolute value on the top).
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