[autoloanexpert]

why would a stock have value if it doesn't pay dividends

[offemyJuccete]

Partial ownership/etc?

JM

[AngelinaTheElf]

Oh I figured it out.

from Pt = (K - St)*D(T-t) + Ct
D(T-t) = 1 => Pt > K - St = return from exercising option => you will never exercise option => European and American options are identical

[rozalinasi]

why would a stock have value if it doesn't pay dividends

I hope you are joking

[peemovvie]

I hope you are joking

I wasn't joking. I don't know very much at all about financial math. It was an honest question. However I have since figured it out.

[Mjxhnapi]

stock = stock option?

[pymnConyelell]

Obviously the price of an American option is at least the price of the European option. The point is that if the interest rate is 0 and there are no dividends, it turns out that you never exercise the American option before the expiration so they are the same.

No offense, but I'm pretty sure this math is beyond your training and you couldn't have actually helped me.

[soajerwaradaY]

I know the difference between an option and what it was the option of (I do some agri products' futures), its just that the OP didn't mention option actually it did, I missed it.

[Crilosajsamq]

That would depend if it's a call or put option.

Regardless, someone might sell a call option based purely on the timing of their investments rather than the movement of the stock, forcing them to exercise prior to the expiration date.

[yarita]

If we are talking options in common stock , there may be many opportunities where a real investor might exercise early based on an assessment of the company, industry trends or even recent events. The American option holder may have the chance to exerercie and sell a stock for gain while the European option holder finds no value in the exercise as the stock goes back down prior to expiry.

In fact your assessment that you never exercise an option before expiry day would be true only for stable or rising stocks (if you have a purchase option)

Under a bunch of assumptions you can show that the present value of the American option is always greater than the money you could earn by exercising it, when the stock pays no dividends and the risk-free rate is 0, i.e. no rational investor would exercise the option prior to expiration.

Obviously, several of these assumptions aren't actually true. They are useful mathematical constructs.

[soitlyobserty]

I'm a physicist, not an economist!

You're not a physicist, you piece of ****.

[kvitacencia]

If we are talking options in common stock , there may be many opportunities where a real investor might exercise early based on an assessment of the company, industry trends or even recent events. The American option holder may have the chance to exerercie and sell a stock for gain while the European option holder finds no value in the exercise as the stock goes back down prior to expiry.

In fact your assessment that you never exercise an option before expiry day would be true only for stable or rising stocks (if you have a purchase option)

/

This post is utterly ridiculous. I suggest you read a basic financial math book. Real investors, if they wish to take a market view, will resell the option for >= the intrinsic value in the market (strictly greater if implied volatility is anything other than 0). If the price was ever less than the intrinsic value then there exists a simple arbitrage. Exercising early is always suboptimal, modulo transaction costs and some minor difficulties like shorting at a retail level.

[ZesePreodaNed]

That's physician.

[gactanync]

No. You're in what, HS?

Do two years and you'll have the same.

I've taken college level physics you dumb ****

[ElenaEvgeevna]

Ok i've now ADBLOCKED ben kenobi to avoid any temptation to view his posts
jesus christ I don't understand how someone so stupid can even be literate
adblock

[janeemljr]

Two years? Did he get an associate's degree or something?

[twinaircant]

This is like watching two paraplegics run a marathon.

[Eujacwta]

A long uniform slab of with mass M is sliding on a "frictionless" horizontal surface with (constant) speed S before a small, dense block with mass 2M is placed on top of the front of it by a person nearby. The small block has an initial velocity of ZERO with respect to the fixed horizontal surface so it immediately starts skidding along the surface of the moving slab. The coefficient of kinetic friction between the block and slab is Mu . As the block skids the slab slows down until the velocities of both objects with respect to the fixed surface are identical; after which they move together. ( The block does NOT reach the back of the slab and fall off!)

a) Develop an expression for the time it takes the block and slab to reach the same velocity. Express your answer in terms of g, Mu, and S.
b) Find an expression for the final speed of both objects with respect to the fixed surface.
c) Find the magnitude of the frictional force between the objects once the slab and block are both gliding with the same speed.

[Immarsecice]

This is like watching two paraplegics run a marathon.

Ok I concede that I'm not as good at physics as you
I think this is to be expected. Sorry

At least I'm not like ben--I don't think I'm a physicist.

[hellencomstar]

It's not even a very hard problem...basic mechanics