[tetMitshisk]

>>>p=rho x g x h where rho = density of fluid and h is height of fluid. If rho, g, or h change, the pressure changes

Math isn't my nearest friend, and sunday math less so, is atmospheric pressure in there, and does it make any difference?

[yWleIJm4]

atmospheric pressure will be working the same on both ends unless you have a very long pipe with one end in a high pressure area and the other in a low. think of the water height inside the eye of a cyclone for instance.

[sEe]

In answer to the question, the total force for any defined area X is the same for both examples.

[botagozzz]

i think that was mentioned in the second post.

:-)

[vintsqyuid]

>>>i think that was mentioned in the second post.

:-)

Like to pretend to come to these things independently, that I missed the train and walked lets me time to enjoy the view.

[AutoCadPhotoSHOP]

make that incompressible,

[gagagaridze]

>>>p=rho x g x h where rho = density of fluid and h is height of fluid. If rho, g, or h change, the pressure changes

Math isn't my nearest friend, and sunday math less so, is atmospheric pressure in there, and does it make any difference?

Yes as far as I know. A storm surge is created from a very low pressure therefore the higher pressure around it will be drawn into the low pressure area and increase the height of the ocean.

[zoneouddy]

A 10kpa pressure differance will increase the height by 1 metre.

[RichardFG435]

I weigh about 1006 Newtons.

Or rather, your feet press the ground with a total of 1006 N force.


....waits for consequences of contradicting MWF...

[sttrqiss]

Supposing gravity is equal everywhere on earth (which it is not) how much would centripetal force at the equator reduce your effective weight compared with at the poles?

[spoddersedpn]

By mv^2/r, if 'u want numbers I'l have to find a better platform to post from at some later time.

[orison]

Supposing gravity is equal everywhere on earth (which it is not) how much would centripetal force at the equator reduce your effective weight compared with at the poles?

0.3%

[kuzbaslachek]

... or, if you take oblateness into account, 0.5%