need help on a calc. problem - DiscussWorldIssues - Socio-Economic Religion and Political Uncensored Debate

**GarryPaterson** · 10-17-2006, 11:28 AM

find d^2y/d^2x of x^2y^2 - 2x = 3

I got (-2x^-2y^-1 + x^-1y)/(x^-1 + 1) which doesn't look right and I can't seem to simplify it so I have positive exponents.

**AdvertisingPo** · 10-17-2006, 04:48 PM

Err... you don't necessarily need positive exponents...

**Cajlwdvx** · 10-17-2006, 10:09 PM

The answer is clearly 5.

**Frannypaync** · 10-17-2006, 10:19 PM

i was lost at "find"

**priceyicey** · 10-17-2006, 10:37 PM

Something stinks...why do you still have a y?

x^2*y^2 - 2x =3 right?

so x^2*y^2 = 3+2x ==> y^2 = (3+2x)/x^2 ==> y = ((3+2x)/x^2)^1/2

Can't you solve from that for an expression of d^2y/d^2x?

10-17-2006, 11:28 AM	#1
GarryPaterson Join Date Oct 2005 Posts 354 Senior Member	need help on a calc. problem find d^2y/d^2x of x^2y^2 - 2x = 3 I got (-2x^-2y^-1 + x^-1y)/(x^-1 + 1) which doesn't look right and I can't seem to simplify it so I have positive exponents. Share Share this post on Digg Del.icio.us Technorati Twitter
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10-17-2006, 04:48 PM	#2
AdvertisingPo Join Date Oct 2005 Posts 477 Senior Member	Err... you don't necessarily need positive exponents... Share Share this post on Digg Del.icio.us Technorati Twitter
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10-17-2006, 10:09 PM	#3
Cajlwdvx Join Date Oct 2005 Posts 654 Senior Member	The answer is clearly 5. Share Share this post on Digg Del.icio.us Technorati Twitter
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10-17-2006, 10:19 PM	#4
Frannypaync Join Date Nov 2005 Posts 402 Senior Member	i was lost at "find" Share Share this post on Digg Del.icio.us Technorati Twitter
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10-17-2006, 10:37 PM	#5
priceyicey Join Date Oct 2005 Posts 451 Senior Member	Something stinks...why do you still have a y? x^2y^2 - 2x =3 right? so x^2y^2 = 3+2x ==> y^2 = (3+2x)/x^2 ==> y = ((3+2x)/x^2)^1/2 Can't you solve from that for an expression of d^2y/d^2x? Share Share this post on Digg Del.icio.us Technorati Twitter
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